/Shell/Bash/Bash print specific range of rows from a file

Bash print specific range of rows from a file

# Basic syntax with sed:
sed -n 'start,endp' input_file.txt
# Where start and end are numbers that inclusively define the range. E.g.
sed -n '17,23p' input_file.txt # To print the [17-23] rows

Similar codes

0 vote182 views1 answer
Git bash remove files with extension recursively
Shell/Bash
5 votes208 views2 answers
Change ownership of a directory in ubuntu
Shell/Bash
0 vote194 views1 answer
The repository 'https://download.docker.com/linux/ubuntu bionic InRelease' is not signed.
Shell/Bash
2 votes273 views1 answer
Nginx post size
Shell/Bash
0 vote191 views1 answer
You should recreate configure.ac:7: aclocal.m4 with aclocal and run automake again.
Shell/Bash
9 votes179 views4 answers
Install react native cli
Shell/Bash
74 votes165 views6 answers
Kill process running on port mac
Shell/Bash
1 vote184 views2 answers
Gitignore for django project
Shell/Bash
0 vote185 views1 answer
Disable the built-in Redis and Fill in the connection details
Shell/Bash
0 vote218 views1 answer
Cat along with line numbers
Shell/Bash