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Python remove all occurrence of an items from list

Remove all occurrences of a character in a list python

>>> x = [1,2,3,2,2,2,3,4]
>>> list(filter(lambda a: a != 2, x))
[1, 3, 3, 4]

Source: stackoverflow.com

Python remove all occurrence of an items from list

rec1=[88,23,7,66,88,7,2,88,90]
def removes(lst,item):
    rems= lst.count(item) # count number of times the item occurs e.g 7 appears twice
    if not rems: # return if item does not occur in the list
        return    
    for i in range(rems): #loop through the number occurrences
        lst.remove(item) #remove each occurrence
 
removes(rec1,7)

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