Dataframe rank groupby

>>> df["rank"] = df.groupby("group_ID")["value"].rank("dense", ascending=False)
>>> df
     group_ID item_ID  value  rank
0  0S00A1HZEy      AB     10     2
1  0S00A1HZEy      AY      4     3
2  0S00A1HZEy      AC     35     1
3  0S03jpFRaS      AY     90     1
4  0S03jpFRaS      A5      3     5
5  0S03jpFRaS      A3     10     2
6  0S03jpFRaS      A2      8     4
7  0S03jpFRaS      A4      9     3
8  0S03jpFRaS      A6      2     6
9  0S03jpFRaS      AX      0     7

Source: stackoverflow.com

Similar codes

15 votes138 views2 answers
!.gitignore
Python
1 vote166 views1 answer
Read a function of excel in python
Python
1 vote169 views1 answer
Multiprocessing a for loop python
Python
0 vote158 views1 answer
Python cgi get raw post data
Python
0 vote153 views1 answer
Username python system
Python
0 vote187 views1 answer
Save_img keras
Python
1 vote165 views1 answer
Python delete text in text file
Python
8 votes154 views2 answers
Selenium upload file python
Python
1 vote160 views1 answer
SQL Query to Join Two Tables Based Off Closest Timestamp
Python
-1 vote139 views1 answer
Function TBone() if 2=2 then print("Sup") end
Python