Dataframe rank groupby

>>> df["rank"] = df.groupby("group_ID")["value"].rank("dense", ascending=False)
>>> df
     group_ID item_ID  value  rank
0  0S00A1HZEy      AB     10     2
1  0S00A1HZEy      AY      4     3
2  0S00A1HZEy      AC     35     1
3  0S03jpFRaS      AY     90     1
4  0S03jpFRaS      A5      3     5
5  0S03jpFRaS      A3     10     2
6  0S03jpFRaS      A2      8     4
7  0S03jpFRaS      A4      9     3
8  0S03jpFRaS      A6      2     6
9  0S03jpFRaS      AX      0     7

Source: stackoverflow.com

Similar codes

0 vote162 views2 answers
Scrapy capture: Error downloading
Python
-1 vote162 views2 answers
Python check if string has space
Python
-1 vote202 views1 answer
Gdscript iterate over dictionary
Python
10 votes158 views1 answer
Python - convert a column in a dataframe into a list
Python
114 votes161 views5 answers
How to use inputs in python
Python
0 vote163 views1 answer
Python graphviz undirected graph
Python
0 vote231 views1 answer
Flask send email gmail
Python Flask
0 vote212 views2 answers
From django.core.management import execute_from_command_line ImportError: No module named django.core.management
Python Django
2 votes173 views3 answers
Nested dictionary Python
Python
1 vote170 views4 answers
Table
Python