Classement rang mysql 7

Bill    32  M   4
Bob     25  M   2
Jack    30  M   3
Nick    22  M   1
Steve   36  M   5
Anne    25  F   3
Jane    20  F   2
Kathy   18  F   1

Source: qastack.fr

Classement rang mysql 7

SELECT    a.first_name,
      a.age,
      a.gender,
        count(b.age)+1 as rank
FROM  person a left join person b on a.age>b.age and a.gender=b.gender 
group by  a.first_name,
      a.age,
      a.gender

Source: qastack.fr

Classement rang mysql 7

CREATE TABLE person (id int, first_name varchar(20), age int, gender char(1));

INSERT INTO person VALUES (1, 'Bob', 25, 'M');
INSERT INTO person VALUES (2, 'Jane', 20, 'F');
INSERT INTO person VALUES (3, 'Jack', 30, 'M');
INSERT INTO person VALUES (4, 'Bill', 32, 'M');
INSERT INTO person VALUES (5, 'Nick', 22, 'M');
INSERT INTO person VALUES (6, 'Kathy', 18, 'F');
INSERT INTO person VALUES (7, 'Steve', 36, 'M');
INSERT INTO person VALUES (8, 'Anne', 25, 'F');

Source: qastack.fr

Similar codes

1 vote196 views1 answer
Sql padd let with zeros
SQL
0 vote234 views1 answer
Reindexing all tables sql server
SQL
15 votes191 views2 answers
How to drop database name in postgresql
SQL
7 votes194 views4 answers
How to reset the identity column in sql server
SQL
25 votes213 views5 answers
Uninstall mysql ubuntu
SQL
2 votes180 views2 answers
Postgresql date at timezone
SQL
0 vote197 views2 answers
Temp Space
SQL
0 vote182 views1 answer
Minecraft duping allowed servers
SQL
0 vote233 views1 answer
Sql query tags
SQL
1 vote175 views1 answer
Mysql batch insert
SQL