Check status code urllib

import urllib.request, urllib.error

url = 'http://www.google.com/asdfsf'
try:
    conn = urllib.request.urlopen(url)
except urllib.error.HTTPError as e:
    # Return code error (e.g. 404, 501, ...)
    # ...
    print('HTTPError: {}'.format(e.code))
except urllib.error.URLError as e:
    # Not an HTTP-specific error (e.g. connection refused)
    # ...
    print('URLError: {}'.format(e.reason))
else:
    # 200
    # ...
    print('good')

Source: stackoverflow.com

Check status code urllib

import urllib2

req = urllib2.Request('http://www.python.org/fish.html')
try:
    resp = urllib2.urlopen(req)
except urllib2.HTTPError as e:
    if e.code == 404:
        # do something...
    else:
        # ...
except urllib2.URLError as e:
    # Not an HTTP-specific error (e.g. connection refused)
    # ...
else:
    # 200
    body = resp.read()

Source: stackoverflow.com

Similar codes

6 votes189 views2 answers
Isnumeric
Python
0 vote132 views1 answer
Split string by delimiter string
Python
7 votes185 views3 answers
How to get all possible combinations in python
Python
21 votes182 views6 answers
Python simple server
Python
8 votes185 views6 answers
Def function python
Python
16 votes190 views6 answers
List.add in python
Python
10 votes180 views3 answers
Python click on screen
Python
0 vote182 views3 answers
Dataset for cancer analysis in python
Python
0 vote181 views1 answer
Pandas filter column greater than
Python
4 votes173 views4 answers
Set python3.7 as default ubuntu
Python