Django reverse

from django.urls import reverse

def myview(request):
    return HttpResponseRedirect(reverse('arch-summary', args=[1945]))

Source: docs.djangoproject.com

Django reverse

return HttpResponseRedirect(reverse('blogIndex', args=[str(pk)]))

Django reverse lazy

class NewJobCBV(LoginRequiredMixin, CreateView):
    template_name = 'company/job.html'
    form_class = newJobForm
    # success_url = reverse_lazy('newJob')

    def get_success_url(self, **kwargs):
        return reverse("newJob")

-2

Source: stackoverflow.com

Similar codes

0 vote236 views1 answer
Include app in django project
Python Django
3 votes323 views2 answers
Django get parameters from url
Python Django
0 vote231 views1 answer
Django create object with default today date
Python Django
3 votes276 views2 answers
Django change user password
Python Django
8 votes246 views3 answers
Django sort queryset
Python Django
0 vote231 views1 answer
Django active link
Python Django
0 vote196 views1 answer
Django admin manytomanyfield filter
Python Django
1 vote223 views1 answer
Filter foreign fileds django_filters
Python Django
4 votes336 views2 answers
Django composite primary key
Python Django
0 vote263 views1 answer
Render django views
Python Django