Numpy.where() for substring

foo = 'aa'
bar = np.array(['aaa', 'aab', 'aca'])
out = [i for i, v in enumerate(bar) if foo in v]
# out = [0, 1]

bar = ['aca', 'bba', 'baa', 'aaf', 'ccc']
out = [i for i, v in enumerate(bar) if foo in v]
# out = [2, 3]

Source: stackoverflow.com

Similar codes

3 votes171 views1 answer
Numpy array count frequency
Python
0 vote185 views1 answer
Python input for competitive programming
Python
0 vote210 views1 answer
Seconds to time python
Python
0 vote178 views1 answer
Download python 3.8
Python
0 vote183 views1 answer
How to remove a list of numbers from a list in python
Python
0 vote192 views1 answer
Numpy savetext in one line
Python
11 votes242 views3 answers
Python replace string in file
Python
1 vote226 views1 answer
Django filter by date range
Python Django
8 votes171 views1 answer
Expand all rows pandas
Python
2 votes215 views1 answer
Django register models
Python Django