Php regex markdown link

$text = 'Link to [Google](https://www.google.com/)';
echo preg_replace('/\[(.*?)\]\s*\(((?:http:\/\/|https:\/\/)(?:.+))\)/', '<a href="$2">$1</a>', $text);
// Outputs: Link to <a href="https://www.google.com/">Google</a>

Source: stackoverflow.com

Similar codes

48 votes141 views6 answers
Join in laravel
PHP
0 vote164 views1 answer
Img src php wordpress theme child
PHP Wordpress
0 vote151 views1 answer
How to remove notice error in php
PHP
0 vote150 views2 answers
Php curl ssl verify
PHP
0 vote240 views1 answer
Add element to this array
PHP
0 vote170 views1 answer
Wordpresss loop through object
PHP
2 votes147 views1 answer
Php trim array to certain length
PHP
0 vote152 views1 answer
Php into javascript
PHP
9 votes185 views4 answers
Convert laravel hash password online
PHP Laravel
0 vote150 views1 answer
Remove space and line from json in php
PHP