Reverse int array java

Reverse array in java

int length = array.length;
		for(int i=0;i<length/2;i++) {
			int swap = array[i];
			array[i] = array[length-i-1];
			array[length-i-1] = swap;
		}
or
Collections.reverse(Arrays.asList(array));

Reverse a integer in java

while(num != 0) 
{
   int digit = num % 10;
   reversed = reversed * 10 + digit;
   num /= 10;
}

Reverse int array java

import java.util.*;
import java.util.stream.Collectors;

int[] array = new int[] {23, 54, 12};
List<Integer> list = Arrays.stream(array).boxed().collect(Collectors.toList());
Collections.reverse(list);
array = list.stream().mapToInt(x -> x).toArray();
//array = [12,54,23]

Reverse array java

//With Commons.Lang, you could simply use

ArrayUtils.reverse(int[] array)

// For reversing subarray
ArrayUtils.reverse(int[] array,int startIndexInclusive, int endIndexExclusive)

Source: stackoverflow.com

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Int a[ ]={4,8,3,2}; a[0] = 23; a[3]= a[1]; a[2]=12; for(int i=0; i<a.length; i++) System.out.println(a[i]);
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