/Python/How to print error in try except python

How to print error in try except python

try:
  # some code
except Exception as e:
	print("ERROR : "+str(e))

Python exception

try:
  # code block
except ValueError as ve:
  print(ve)

Catch error python

import traceback

dict = {'a':3,'b':5,'c':8}
try:
  print(dict[q])
 
except:
  traceback.print_exc()
  
# This will trace you back to the line where everything went wrong. 
# So in this case you will get back line 5

Catch error data with except python

import sys
try:
	S = 1/0 #Create Error
except: # catch *all* exceptions
    e = sys.exc_info()
    print(e) # (Exception Type, Exception Value, TraceBack)

############
#    OR    #
############
try:
	S = 1/0
except ZeroDivisionError as e:
    print(e) # ZeroDivisionError('division by zero')

Python try except: print error

except Exception as e:

Source: kite.com

Python try except print error

   1 (x,y) = (5,0)
   2 try:
   3   z = x/y
   4 except ZeroDivisionError as e:
   5   z = e # representation: "<exceptions.ZeroDivisionError instance at 0x817426c>"
   6 print z # output: "integer division or modulo by zero"

-1

Similar codes

1 vote128 views1 answer
Python for loop even numbers
Python
1 vote150 views1 answer
Django template tags capitalize
Python Django
1 vote147 views1 answer
How to pass data between views django
Python
1 vote75 views1 answer
Create pyspark session with hive support
Python
1 vote110 views1 answer
Required_fields = []
Python
7 votes129 views2 answers
How to generate requirements.txt django
Python Django
0 vote119 views1 answer
Length of number without using len function
Python
0 vote81 views1 answer
Fibonacci series in python using while loop
Python
0 vote122 views1 answer
Split a string into N equal parts.
Python
2 votes111 views2 answers
Create django user command line
Python