/Python/Retrieve content inside the meta tag python

Retrieve content inside the meta tag python

title = soup.find("meta",  property="og:title")
url = soup.find("meta",  property="og:url")

print(title["content"] if title else "No meta title given")
print(url["content"] if url else "No meta url given")

Source: stackoverflow.com

Retrieve content inside the meta tag python

#!/usr/bin/env python
# -*- coding: utf-8 -*-

#importing the libraries
from urllib import urlopen
from bs4 import BeautifulSoup

def get_data(page_no):
    webpage = urlopen('http://superfunevents.com/?p=' + str(i)).read()
    soup = BeautifulSoup(webpage, "lxml")
    for tag in soup.find_all("article") :
        id = tag.get('id')
        print id
# the hard part that doesn't work - I know this example is well off the mark!        
    title = soup.find("og:title", "content")
    print (title.get_text())
    url = soup.find("og:url", "content")
    print (url.get_text())
# end of problem

for i in range (1,100):
    get_data(i)

Source: stackoverflow.com

Retrieve content inside the meta tag python

soup = BeautifulSoup(webpage)
for tag in soup.find_all("meta"):
    if tag.get("property", None) == "og:title":
        print tag.get("content", None)
    elif tag.get("property", None) == "og:url":
        print tag.get("content", None)

Source: stackoverflow.com

Similar codes

0 vote146 views1 answer
How to vonvert 1 d list to 2d list in pytohn
Python
15 votes140 views6 answers
Dataframe to list
Python
0 vote143 views2 answers
Python stopwords not defined
Python
0 vote135 views1 answer
How to get one csv column in python
Python
10 votes148 views4 answers
How to check if Python is 32 or 64 bit
Python
7 votes150 views3 answers
How to get file name without extension in python
Python
0 vote151 views1 answer
Connect snowflake with python
Python
1 vote236 views1 answer
Add help text in Django model forms
Python Django
0 vote138 views1 answer
Python getter decorator
Python
6 votes173 views3 answers
How to split an input in python by comma
Python