/Shell/Bash/Dos assign carriage return to variable

Dos assign carriage return to variable

set myLinefeed=^<LF1>
<LF2>
<LF3>

Source: stackoverflow.com

Dos assign carriage return to variable

setlocal EnableDelayedExpansion
set LF=^


rem TWO empty lines are required
echo This text!LF!uses two lines

Source: stackoverflow.com

Dos assign carriage return to variable

(SET LF=^
%=this line is empty=%
)

Source: stackoverflow.com

Dos assign carriage return to variable

set LF=^


rem TWO empty lines are required
echo This text^%LF%%LF%uses two lines
echo This also^

uses two lines

Source: stackoverflow.com

Dos assign carriage return to variable

if "!LF!" NEQ "!LF:~0,1!" echo Error "Linefeed definition is defect, probably multiple invisble whitespaces at the line end in the definition of LF"

FOR /F "delims=" %%n in ("!LF!") do (
  echo Error "Linefeed definition is defect, probably invisble whitespaces at the line end in the definition of LF"
)

Source: stackoverflow.com

Similar codes

0 vote147 views1 answer
Access wiindows host from wsl2
Shell/Bash
3 votes133 views2 answers
Git gui
Shell/Bash
-1 vote135 views2 answers
Install gradle in mac
Shell/Bash
15 votes159 views2 answers
How to unzip using tar
Shell/Bash
0 vote140 views1 answer
Kali linux connect to wifi from terminal
Shell/Bash
5 votes170 views1 answer
Use mock api
Shell/Bash
0 vote141 views1 answer
Grep output of two commands
Shell/Bash
1 vote142 views1 answer
Copy code from one repo to another git
Shell/Bash
0 vote163 views1 answer
Get sentence in folder
Shell/Bash
0 vote121 views1 answer
Yum webmin reinstall
Shell/Bash