/Shell/Bash/Awk print rows that aren't blank in specific field

Awk print rows that aren't blank in specific field

# Basic syntax:
awk -F'delimiter' '$column# != ""' input_file

# Example usage:
awk -F'\t' '$3 != ""' input_file
# This prints every line in which the 3rd tab-delimited column is 
# not blank. Change the 3 to any column and/or add other conditions 
# for your application

Source: unix.com

Similar codes

0 vote200 views1 answer
Git bash in cmd
Shell/Bash
-3 votes192 views6 answers
Flush dns
Shell/Bash
70 votes216 views6 answers
Docker remove
Shell/Bash
3 votes190 views5 answers
Zsh shell
Shell/Bash
0 vote191 views1 answer
"serverless-prune-plugin" not found.
Shell/Bash
0 vote278 views1 answer
Ubuntu turn off monitor
Shell/Bash
1 vote197 views1 answer
How to fix flash
Shell/Bash
1 vote200 views1 answer
Ubuntu folder size
Shell/Bash
0 vote225 views1 answer
Uninstall a rpm
Shell/Bash
0 vote212 views1 answer
Docker build linux/amd64
Shell/Bash