/Python/Python find matching string regardless of case

Python find matching string regardless of case

# credit to the Stack Overflow users in the source lin
# with regex
import re
if re.search('mandy', 'Mandy Pande', re.IGNORECASE):
   # do your stuff here
   # Note:
   # results = re.search('mandy', 'Mandy Pande', re.IGNORECASE)
   # results.group(0) is the string that matched ('Mandy')

# without regex
string1 = "hi"
string2 = "HI"
if string1.lower() == string2.lower():
    print("Equals!")
else:
    print("Different!")

Source: stackoverflow.com

Similar codes

0 vote136 views1 answer
Add columns not in place
Python
0 vote137 views1 answer
Calculate Euclidean Distance in Python using norm()
Python
6 votes190 views1 answer
Jupyter pdataframe max rows
Python
0 vote144 views1 answer
Qt platform plugin could not be initialized stackoverflow
Python
0 vote140 views1 answer
Python search a string in another string get last result
Python
4 votes135 views2 answers
Mode code python
Python
0 vote137 views4 answers
Django-sslserver · PyPI
Python
1 vote138 views1 answer
Python requests set header cookie
Python
0 vote137 views1 answer
Python max of two numbers
Python
0 vote155 views1 answer
12000000/12
Python