/Python/Python find matching string regardless of case

Python find matching string regardless of case

# credit to the Stack Overflow users in the source lin
# with regex
import re
if re.search('mandy', 'Mandy Pande', re.IGNORECASE):
   # do your stuff here
   # Note:
   # results = re.search('mandy', 'Mandy Pande', re.IGNORECASE)
   # results.group(0) is the string that matched ('Mandy')

# without regex
string1 = "hi"
string2 = "HI"
if string1.lower() == string2.lower():
    print("Equals!")
else:
    print("Different!")

Source: stackoverflow.com

Similar codes

9 votes230 views2 answers
Django import Q
Python Django
8 votes273 views4 answers
How to change icon in pygame
Python
7 votes198 views3 answers
Clear all python cache
Python
0 vote286 views1 answer
Rolling window 2d array
Python
0 vote192 views1 answer
Create array with unknown size in python
Python
0 vote189 views1 answer
Selenium python has no attrirute getText
Python
4 votes218 views1 answer
Urlpatterns = [ path('SignUp/', views.SignupPage, name='user_data')\
Python
22 votes202 views5 answers
Python palindrome check
Python
0 vote190 views1 answer
Scipy version check
Python
0 vote187 views1 answer
Subplot adjust python
Python