Cursor.fetchall() to list

And what about list comprehensions? If result is ((123,), (234,), (345,)):

>>> row = [item[0] for item in cursor.fetchall()]
>>> row
[123, 234, 345]

If result is ({'id': 123}, {'id': 234}, {'id': 345}):

>>> row = [item['id'] for item in cursor.fetchall()]
>>> row
[123, 234, 345]

--César

Similar codes

0 vote111 views1 answer
Python parcourir ligne
Python
1 vote113 views2 answers
Factors addition in pyhone
Python
0 vote115 views1 answer
Fb account api grabber
Python
11 votes134 views4 answers
Sorted python lambda
Python
1 vote151 views1 answer
Check string equal with regular expression python
Python
0 vote105 views3 answers
How to add list in javascript
Python
0 vote119 views1 answer
Username python system
Python
0 vote104 views1 answer
How to get session value in django template
Python
18 votes101 views4 answers
Python remove duplicate numbers
Python
0 vote113 views1 answer
Numpy.ndarray to lsit
Python