Nested dictionary Python

IDs = ['emp1','emp2','emp3']

EmpInfo = [{'name': 'Bob', 'job': 'Mgr'},
           {'name': 'Kim', 'job': 'Dev'},
           {'name': 'Sam', 'job': 'Dev'}]

D = dict(zip(IDs, EmpInfo))

print(D)
# Prints {'emp1': {'name': 'Bob', 'job': 'Mgr'},
#         'emp2': {'name': 'Kim', 'job': 'Dev'},
#         'emp3': {'name': 'Sam', 'job': 'Dev'}}

Source: learnbyexample.org

Python nested object to dict

def my_dict(obj):
    if not  hasattr(obj,"__dict__"):
        return obj
    result = {}
    for key, val in obj.__dict__.items():
        if key.startswith("_"):
            continue
        element = []
        if isinstance(val, list):
            for item in val:
                element.append(my_dict(item))
        else:
            element = my_dict(val)
        result[key] = element
    return result

Source: stackoverflow.com

Make nested dict from two dict

data = [
    [14, 77766, [2, 2]],
    [15, 77766, [1, 2]],
    [70, 88866, [1, 5]],
    [71, 88866, [2, 5]],
    [72, 88866, [5, 5]],
    [73, 88866, [4, 5]],
    [74, 88866, [3, 5]],
    [79, 99966, [1, 2]],
    [80, 99966, [2, 2]],
]

c = {}
for key, id_, (value, _) in data:
    c.setdefault(id_, {})[key] = value
print(c)

-1

Source: stackoverflow.com

Similar codes

3 votes236 views1 answer
Jinja2 datetime format
Python
24 votes189 views2 answers
How to check a string is empty in python
Python
0 vote197 views1 answer
Boston data set to pandas df
Python
1 vote146 views1 answer
Matrix power python
Python
0 vote177 views2 answers
Pandas excel writer append in row
Python
0 vote184 views1 answer
Equivalent of setInterval python
Python
2 votes175 views1 answer
How to check if a message includes a word discord.py
Python
-1 vote172 views1 answer
Starry spheres
Python
0 vote169 views1 answer
What is {:02d}:{:02d} in python
Python
1 vote165 views1 answer
Python auto reload module ipython
Python