/Python/Django create view filter options

Django create view filter options

class FolderForm(forms.ModelForm):
    class Meta:
       model = Folder
       fields = ['name', 'parent']

    def __init__(self, *args, **kwargs):
       user = kwargs.pop('user')
       super(FolderForm, self).__init__(*args, **kwargs)
       self.fields['parent'].queryset = Folder.objects.filter(user=user)

Source: stackoverflow.com

Django create view filter options

class FolderCreate(CreateView):
    template_name = 'Form/folder_create.html'
    form_class = FolderForm

    def get_form_kwargs(self):
        kwargs = super(FolderCreate, self).get_form_kwargs()
        kwargs['user'] = self.request.user
        return kwargs

Source: stackoverflow.com

Similar codes

0 vote138 views1 answer
Python pandas first and last element of column
Python
0 vote143 views1 answer
Python search resultset from finadall
Python
9 votes137 views2 answers
Fill missing values in column pandas with mean
Python
0 vote155 views1 answer
Unbreakable box made of diamond
Python
47 votes138 views3 answers
String to array python
Python
1 vote153 views1 answer
Requirements.py for flask
Python
39 votes144 views6 answers
Python list contains string
Python
0 vote139 views1 answer
Python Split list into chunks using for loop
Python
0 vote138 views1 answer
Only split from third delimiter python
Python
0 vote155 views1 answer
Pandas eliminar filas de un dataframe con una condicion
Python