/Shell/Bash/Swapping of two numbers without using third variable in shell script

Swapping of two numbers without using third variable in shell script

#!/bin/bash
echo "enter first number"
read a
echo "enter second number"
read b
echo "a before swapping is $a and b is $b"
#swapping
a=$((a+b))
b=$((a - b))
a=$((a-b))
echo "a after swapping is  $a and b is $b"

Source: technicalworldforyou.blogspot.com

Similar codes

0 vote160 views1 answer
Rename all files in a folder with progressive numbers linux
Shell/Bash
2 votes188 views3 answers
Install nuxt
Shell/Bash
0 vote169 views1 answer
How t o force install a package even it is already install pip
Shell/Bash
0 vote184 views1 answer
Add features for wsl linux
Shell/Bash
0 vote110 views2 answers
How to setup ssh keys
Shell/Bash
2 votes149 views2 answers
Wget debian
Shell/Bash
0 vote152 views1 answer
Run same command in different hosts
Shell/Bash
0 vote158 views1 answer
PHP Fatal error: Uncaught Error: Call to undefined function Moontoast\Math\bcadd() in /var/www/html/sms-reporting-portal/vendor/moontoast/math/src/Moontoast/Math/BigNumber.php:506
Shell/Bash
91 votes148 views6 answers
Docker remove all image
Shell/Bash
1 vote144 views1 answer
Ubuntu install java JRE 1.8.0_152
Shell/Bash