/Python/Search for a symmetrical inner elements of a list python

Search for a symmetrical inner elements of a list python

def symmetrical_sum(a):
    dup=[x for n, x in enumerate(a) if x in a[:n]] #to get the duplicate
    
    to_int = int(''.join(map(str,dup))) #change duplicate into int
    dup1_index=a.index(to_int) #index the first duplicate
    dup2_index=a.index(to_int,dup1_index+1) #index the second duplicate
    portion=a[dup1_index:dup2_index+1] #get the symetric portion
    total = sum(portion) #sum the elements in portion
    tuple1 = (portion,total) #create tuple
    return tuple1

Source: stackoverflow.com

Similar codes

4 votes160 views2 answers
Make a nested list flat python
Python
7 votes146 views3 answers
How to exit venv in python
Python
0 vote209 views1 answer
Relation api profile does not exist django
Python Django
4 votes196 views2 answers
How to use ternary operater in python
Python
109 votes140 views6 answers
Python check if string contains substring
Python
2 votes174 views4 answers
Python slow print
Python
1 vote134 views1 answer
Get csrf_token value in django template
Python
1 vote138 views1 answer
Django httpresponseredirect
Python
0 vote102 views1 answer
Python regex end with
Python
0 vote139 views4 answers
Python draw circle matplotlib
Python