Dictionary comprehension python

Python dictionary comprehension

dict1 = {'a': 1, 'b': 2, 'c': 3, 'd': 4, 'e': 5}
# Double each value in the dictionary
double_dict1 = {k:v*2 for (k,v) in dict1.items()}
# double_dict1 = {'e': 10, 'a': 2, 'c': 6, 'b': 4, 'd': 8} <-- new dict

Source: datacamp.com

Dictionary comprehension python

square_dict = {num: num*num for num in range(1, 11)}

Source: grepper.com

Python dictionary comprehension

users = {'sam': 20, 'mike': 30, 'joe': 40}

# return users where the ave is greater than 20
users_over_20 = {k: v for k, v in users.items() if v > 20}

# print users over 20
print(users_over_20)
# output {'mike': 30, 'joe': 40}

Source: codefreelance.net

Dictionary comprehension python

print({i:j for i,j in zip(txt_list,num) if i!="All"})

Source: grepper.com

Python dictionary comprehensions

names = ['Bruce', 'Clark', 'Peter', 'Logan', 'Wade']
heros = ['Batman', 'Superman', 'Spiderman', 'Wolverine', 'Deadpool']

my_dict= {name: hero for name, hero in zip(name,hero)}

Source: datacamp.com

Python Dictionary Comprehension

# Dictionary Comprehension
squares = {x: x*x for x in range(6)}

print(squares)

Source: grepper.com

Dict comprehension

# Dictionary comprehension

{i:i*2 for i in range(10)}

Source: grepper.com

Dict comprehensions

>>> print {i : chr(65+i) for i in range(4)}
{0 : 'A', 1 : 'B', 2 : 'C', 3 : 'D'}

Source: python.org

Dictionary comprehension

>>> {x: x**2 for x in (2, 4, 6)}
{2: 4, 4: 16, 6: 36}

Source: docs.python.org

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