Python sort dictionary by value

How to sort a dictionary by value in python

import operator
x = {1: 2, 3: 4, 4: 3, 2: 1, 0: 0}
sorted_x = sorted(x.items(), key=operator.itemgetter(1))


# Sort by key
import operator
x = {1: 2, 3: 4, 4: 3, 2: 1, 0: 0}
sorted_x = sorted(x.items(), key=operator.itemgetter(0))

Source: grepper.com

Python - sort dictionary by value

d = {'one':1,'three':3,'five':5,'two':2,'four':4}

# Sort
a = sorted(d.items(), key=lambda x: x[1])

# Reverse sort
r = sorted(d.items(), key=lambda x: x[1], reverse=True)

Source: stackoverflow.com

Python sort array of dictionary by value

my_list = sorted(my_list, key=lambda k: k['name'])

Source: stackoverflow.com

Sort dictionary by value and then key python

sorted(y.items(), key=lambda x: (x[1],x[0]))

Source: stackoverflow.com

Python Sort the dictionary based on values

dt = {5:4, 1:6, 6:3}

sorted_dt = {key: value for key, value in sorted(dt.items(), key=lambda item: item[1])}

print(sorted_dt)

Source: programiz.com

How to sort dictionary in python by value

# your dictionary
a = {'a':4, 'c':5, 'b':3, 'd':0}

# sort x by keys
a_keys = dict(sorted(a.items(),key=lambda x:x[0],reverse = False)) # ascending order
# output: {'a': 4, 'b': 3, 'c': 5, 'd': 0}

# # sort x by values
a_values = dict(sorted(a.items(),key=lambda x:x[1],reverse = False)) # ascending order
# output: {'d': 0, 'b': 3, 'a': 4, 'c': 5}

Source: grepper.com

Python sort dictionary by value

x = {1: 2, 3: 4, 4: 3, 2: 1, 0: 0}

sort_by_key = dict(sorted(x.items(),key=lambda item:item[0]))
sort_by_value = dict(sorted(x.items(), key=lambda item: item[1]))

print("sort_by_key:", sort_by_key)
print("sort_by_value:", sort_by_value)

# sort_by_key: {0: 0, 1: 2, 2: 1, 3: 4, 4: 3}
# sort_by_value: {0: 0, 2: 1, 1: 2, 4: 3, 3: 4

Source: grepper.com

Sort a dictionary by value then key

d = {'apple': 2, 'banana': 3, 'almond':2 , 'beetroot': 3, 'peach': 4}
[v[0] for v in sorted(d.items(), key=lambda kv: (-kv[1], kv[0]))]

Source: stackoverflow.com

Python Sort the dictionary based on values

dt = {5:4, 1:6, 6:3}

sorted_dt_value = sorted(dt.values())
print(sorted_dt_value)

Source: programiz.com

Similar codes

0 vote186 views1 answer
Transformer un dictionnaire en liste python
Python
0 vote196 views1 answer
Video timestamp opencv python
Python
19 votes332 views3 answers
Simplified if else python
Python
0 vote231 views1 answer
Pip install Parser
Python
17 votes196 views4 answers
Python pil resize image
Python
0 vote206 views1 answer
Unindent does not match any outer indentation level
Python
1 vote203 views1 answer
Plt line of best fit
Python
4 votes193 views1 answer
Set column datatype pandas
Python
23 votes364 views5 answers
Flask app example
Python Flask
0 vote225 views1 answer
Python get item from list by index
Python