Matrix power python

Matrix pow python

>>> from numpy.linalg import matrix_power
>>> i = np.array([[0, 1], [-1, 0]]) # matrix equiv. of the imaginary unit
>>> matrix_power(i, 3) # should = -i
array([[ 0, -1],
       [ 1,  0]])
>>> matrix_power(i, 0)
array([[1, 0],
       [0, 1]])
>>> matrix_power(i, -3) # should = 1/(-i) = i, but w/ f.p. elements
array([[ 0.,  1.],
       [-1.,  0.]])

Source: numpy.org

Similar codes

6 votes94 views1 answer
Complex num in python
Python
0 vote135 views1 answer
Logout from linux using python
Python
1 vote120 views2 answers
To see version matplotlib
Python
1 vote130 views1 answer
Python install tabulate
Python
2 votes124 views2 answers
Mode
Python
0 vote135 views1 answer
Nested list in pthon
Python
0 vote117 views1 answer
Raymenschechorne
Python
62 votes136 views6 answers
Os get current directory
Python
22 votes122 views3 answers
Python sort list in reverse order
Python
2 votes116 views1 answer
Set django static root
Python