Anagram

def anagram(a, b):
    return True if sorted(a) == sorted(b) else False

# Based on the answer below :D

Source: grepper.com

Anagram

var firstWord = "Mary";
var secondWord = "Army";

isAnagram(firstWord, secondWord); // true

function isAnagram(first, second) {
  // For case insensitivity, change both words to lowercase.
  var a = first.toLowerCase();
  var b = second.toLowerCase();

  // Sort the strings, and join the resulting array to a string. Compare the results
  a = a.split("").sort().join("");
  b = b.split("").sort().join("");

  return a === b;
}

Source: javascript.plainenglish.io

Anagram

import java.util.Arrays;  
   
public class AnagramString {  
    static void isAnagram(String str1, String str2) {  
        String s1 = str1.replaceAll("\\s", "");  
        String s2 = str2.replaceAll("\\s", "");  
        boolean status = true;  
        if (s1.length() != s2.length()) {  
            status = false;  
        } else {  
            char[] ArrayS1 = s1.toLowerCase().toCharArray();  
            char[] ArrayS2 = s2.toLowerCase().toCharArray();  
            Arrays.sort(ArrayS1);  
            Arrays.sort(ArrayS2);  
            status = Arrays.equals(ArrayS1, ArrayS2);  
        }  
        if (status) {  
            System.out.println(s1 + " and " + s2 + " are anagrams");  
        } else {  
            System.out.println(s1 + " and " + s2 + " are not anagrams");  
        }  
    }  
   
    public static void main(String[] args) {  
        isAnagram("Keep", "Peek");  
        isAnagram("Mother In Law", "Hitler Woman");  
    }  
}

Source: javatpoint.com

Anagram

const anagram = (str1, str2) => {
    return str1.toLowerCase().split('').sort().join('') === str2.toLowerCase().split('').sort().join('');
};

let test = anagram('Regallager', 'Lagerregal');
console.log(test);

Source: grepper.com

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