/Python/Python code for diamond with gap between odd rows

Python code for diamond with gap between odd rows

//pgm for diamond pattern
print("Give the value of n(odd):")
n=int(input())        //input from the user is stored in n
x=n//2+1
//here two loops are combined into one by 'zip'
//loop for printing the first half diamond              
for i,j in zip(range(1,x+1),range(1,n+1,2)):   
    print(' '*(x-i)+'*'*(j))
//loop for printing the second half diamond(reverse half)
for i,j in zip(range(1,x+1),range(n-2,-1,-2)):
    print(' '*(i)+'*'*(j))

Source: geekstocode.com

Similar codes

10 votes125 views4 answers
How to check if Python is 32 or 64 bit
Python
1 vote123 views1 answer
UnicodeDecodeError: 'charmap' codec can't decode byte 0x9d in position 340: character maps to <undefined>
Python
20 votes127 views1 answer
Python time a funciton
Python
0 vote160 views6 answers
Django wht post save signal not firing
Python Django
5 votes140 views4 answers
How print 2 decimal in python
Python
2 votes115 views1 answer
Importying listviewin django
Python
1 vote158 views1 answer
Add background image in django uploaded file
Python
0 vote116 views1 answer
Print convert hex as string ascii
Python
-1 vote148 views1 answer
Binascii.Error: Incorrect padding in python django
Python Django
3 votes123 views1 answer
Spotify api python
Python