/Java/Armstrong Numbers Between Two Integers

Armstrong Numbers Between Two Integers

public class Armstrong {

    public static void main(String[] args) {

        int low = 999, high = 99999;

        for(int number = low + 1; number < high; ++number) {

            if (checkArmstrong(number))
                System.out.print(number + " ");
        }
    }

    public static boolean checkArmstrong(int num) {
        int digits = 0;
        int result = 0;
        int originalNumber = num;

        // number of digits calculation
        while (originalNumber != 0) {
            originalNumber /= 10;
            ++digits;
        }

        originalNumber = num;

        // result contains sum of nth power of its digits
        while (originalNumber != 0) {
            int remainder = originalNumber % 10;
            result += Math.pow(remainder, digits);
            originalNumber /= 10;
        }

        if (result == num)
            return true;

        return false;
    }
}

Source: programiz.com

Similar codes

0 vote138 views2 answers
How to send int value from one actvi to another in android
Java
3 votes152 views2 answers
Random suffling java
Java
5 votes137 views3 answers
Java program to remove duplicate words in a string
Java
1 vote149 views1 answer
How to not open key board on start
Java
7 votes144 views1 answer
Android join list
Java
0 vote145 views1 answer
Doc string in java
Java
7 votes151 views3 answers
Throw and throws keyword in java
Java
46 votes139 views3 answers
How to print out an array in java
Java
0 vote145 views1 answer
Log10 in java
Java
0 vote147 views1 answer
Acceder a elementos de list java
Java