.pop python

Python pop element

my_list = [123, 'Add', 'Grepper', 'Answer']
my_list.pop()
-->[123, 'Add', 'Grepper'] #last element is removed

my_list = [123, 'Add', 'Grepper', 'Answer']
my_list.pop(0)
-->['Add', 'Grepper', 'Answer'] #first element is removed

my_list = [123, 'Add', 'Grepper', 'Answer']
any_index_of_the_list = 2
my_list.pop(any_index_of_the_list)
-->[123, 'Add', 'Answer'] #element at index 2 is removed 
						  #(first element is 0)

Pop function in python

#pop() function
L1 = [20,4,-6,38,-12]
print(' pop', L1.pop())
print('List ', L1)
x=L1.pop(2)
print(' popped:', x)
print('final List :', L1)
#output:
pop -12
List  [20, 4, -6, 38]
popped: -6
final List : [20, 4, 38]

Python list pop

my_list = [-15, 0, 67,45]
print(my_list) # [-15, 0, 67,45]
my_list.pop(3) # 45
print(my_list) # [-15, 0, 67]
my_list.pop(-4) # 0
print(my_list) # [-15,-45,-67]

Source: howtouselinux.com

.pop python

array.pop(2) # removes element at index 2

What does pop do in python

pop python

.pop python

.pop() method

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