Groupby where only

>>> df = pd.DataFrame({'A' : ['foo', 'bar', 'foo', 'bar',
...                           'foo', 'bar'],
...                    'B' : [1, 2, 3, 4, 5, 6],
...                    'C' : [2.0, 5., 8., 1., 2., 9.]})
>>> grouped = df.groupby('A')
>>> grouped.filter(lambda x: x['B'].mean() > 3.)
     A  B    C
1  bar  2  5.0
3  bar  4  1.0
5  bar  6  9.0

-1

Source: pandas.pydata.org

Similar codes

0 vote231 views1 answer
Django phone number
Python Django
0 vote179 views1 answer
Python quick tutorial
Python
14 votes185 views5 answers
How to create requirements.txt django
Python
0 vote203 views1 answer
Mechanize python XE #28
Python
0 vote180 views1 answer
Derivative of multivariable function pytorch
Python
25 votes182 views3 answers
Ndarray to list
Python
0 vote271 views1 answer
Purpose of migration folder in django
Python
0 vote183 views1 answer
How to add list toa key in ict
Python
1 vote177 views1 answer
Downgrade pip
Python
4 votes207 views2 answers
Python dump object print
Python