/Python/How to find if a value is even or odd in python

How to find if a value is even or odd in python

How to check if a number is odd python

num = int(input("Enter a number: "))  
if (num % 2) == 0:  
   print("{0} is Even number".format(num))  
else:  
   print("{0} is Odd number".format(num))

Source: javatpoint.com

How to find if a value is even or odd in python

num = int(input("Enter a Number:"))
if num % 2 == 0:
  print(num , "is even")
else:
  print(num , "is odd")

Odd or even in python

n = int(input("Enter a number: "))
print(n,"is Even.") if (n % 2) == 0 else print(n,"is Odd.")

Similar codes

0 vote138 views1 answer
Discord py server.channels
Python
11 votes151 views2 answers
Format python number with commas
Python
34 votes162 views6 answers
Round python
Python
0 vote146 views1 answer
Python opencv create new image
Python
2 votes170 views2 answers
If else pandas dataframe
Python
0 vote144 views1 answer
What are the mouseX/mouseY variebles in pycharm
Python
0 vote155 views1 answer
How to print the text new line instead of n in jupyter notebook
Python
8 votes105 views4 answers
Reverse dictionary python
Python
3 votes161 views2 answers
Request.get_json() return in flask
Python
1 vote139 views3 answers
Typeerror:
Python