/Python/How to find if a value is even or odd in python

How to find if a value is even or odd in python

How to check if a number is odd python

num = int(input("Enter a number: "))  
if (num % 2) == 0:  
   print("{0} is Even number".format(num))  
else:  
   print("{0} is Odd number".format(num))

Source: javatpoint.com

How to find if a value is even or odd in python

num = int(input("Enter a Number:"))
if num % 2 == 0:
  print(num , "is even")
else:
  print(num , "is odd")

Odd or even in python

n = int(input("Enter a number: "))
print(n,"is Even.") if (n % 2) == 0 else print(n,"is Odd.")

Similar codes

0 vote138 views1 answer
How to python program
Python
0 vote191 views1 answer
Django tempalte tag datetime to timestamp
Python Django
1 vote129 views1 answer
Discord.py dm specific user
Python
0 vote155 views2 answers
Call for a last number in series python
Python
0 vote155 views1 answer
Spark sparsevector to list
Python
63 votes133 views3 answers
How to calculate sum of a list in python
Python
13 votes151 views5 answers
Prime number program in python using function
Python
4 votes107 views2 answers
How to remove all elements from dictionary python
Python
4 votes106 views1 answer
Declaring a numpy array with certain size
Python
8 votes139 views3 answers
Np.arange in python
Python