/Python/How to find if a value is even or odd in python

How to find if a value is even or odd in python

How to check if a number is odd python

num = int(input("Enter a number: "))  
if (num % 2) == 0:  
   print("{0} is Even number".format(num))  
else:  
   print("{0} is Odd number".format(num))

Source: javatpoint.com

How to find if a value is even or odd in python

num = int(input("Enter a Number:"))
if num % 2 == 0:
  print(num , "is even")
else:
  print(num , "is odd")

Odd or even in python

n = int(input("Enter a number: "))
print(n,"is Even.") if (n % 2) == 0 else print(n,"is Odd.")

Similar codes

0 vote149 views1 answer
Removing duplicates using json python
Python
0 vote127 views1 answer
Hover show all Y values in Bokeh
Python
4 votes124 views3 answers
Python create 2d array deep copy
Python
149 votes197 views6 answers
How to make a random number generator in python
Python
0 vote124 views1 answer
Pandas unqiue value each column
Python
0 vote115 views1 answer
How to use self.list.setCurrentRow() in pyqt5
Python
1 vote117 views1 answer
Colab save figure
Python
2 votes148 views1 answer
How store list in django session
Python Django
0 vote119 views1 answer
Tuple push
Python
0 vote117 views1 answer
Count wit for loop pthoon
Python