Malloc in c

#include <stdlib.h>

void *malloc(size_t size);

void exemple(void)
{
  char *string;
  
  string = malloc(sizeof(char) * 5);
  if (string == NULL)
    return;
  string[0] = 'H';
  string[1] = 'e';
  string[2] = 'y';
  string[3] = '!';
  string[4] = '\0';
  printf("%s\n", string);
  free(string);
}

/// output : "Hey!"

C malloc

#include <stdlib.h>
int main(){
int *ptr;
ptr = malloc(15 * sizeof(*ptr)); /* a block of 15 integers */
    if (ptr != NULL) {
      *(ptr + 5) = 480; /* assign 480 to sixth integer */
      printf("Value of the 6th integer is %d",*(ptr + 5));
    }
}

Source: guru99.com

C malloc

Example: ptr = (int *) malloc (50)

Source: guru99.com

Malloc

// if you initialize a pointer and want to use it like an array, 
// you have to claim the space you use, 
// that is what the memory-allocation-funtion (malloc) does;

// exaple for that: str(0) belongs to you, but str(1), str(2), ... do not
// if you do not use the malloc funtion; 
// you can access it, but it could be used by another programm;

#include <stdio.h>
#include <stdlib.h>

void func(void)
{
    char *str = malloc(sizeof(char) * 5); // sizeof --> char needs 
    // a specific space per value saved;
    // *5 --> 5 is the number of values in the array;

    char *str1 = malloc( 5 * sizeof *str1 );//      |
    char *str2 = malloc( sizeof(char[5]) );//       | other syntaxes

    if(str == NULL) { exit(1); } // malloc returns NULL 
    // if it could not allocate the memory;
    str[0] = 'H';
    *(str+1) = 'e';	// used like pointer
    str[2] = 'y';	// used like array
    *(str+3) = '!';
    str[4] = '\0';

    printf("%s\n", str);

    free(str); // frees the memory allocated to str;
    // if you free the memory too early and try to access str later
    // that is called a memory leak;
}

int main(void)
{
    func();
    return 0;
}

// shell: Hey!

// improved version of Thurger's

C malloc

ptr = (cast_type *) malloc (byte_size);

Source: guru99.com

Malloc in c

// Let's allocate enough space on the heap for an array storing 4 ints

intArray = (int *) malloc(4 * sizeof(int)); // A pointer to an array of ints

intArray[0] = 10;
intArray[1] = 20;
intArray[2] = 25;
intArray[3] = 35;

Similar codes

0 vote122 views1 answer
Time random c
C
0 vote112 views1 answer
Stdin char c
C
5 votes107 views2 answers
C malloc array
C
0 vote114 views1 answer
Ssl_get_servername return null
C
0 vote101 views1 answer
Prims and kruskal algorithm
C
1 vote117 views4 answers
Array of strings c
C
4 votes107 views1 answer
Typedef c struct
C
0 vote114 views1 answer
Go Iterating over an array using a range operator
C
1 vote113 views1 answer
C null define
C
0 vote99 views1 answer
Email dev Microsoft Outlook 2007 items all aligned left or aligned wrong
C