/TypeScript/How to sort a list of lists in python

How to sort a list of lists in python

from operator import itemgetter
A = [[10, 8], [90, 2], [45, 6]]
print("Sorted List A based on index 0: % s" % (sorted(A, key=itemgetter(0))))
B = [[50, 'Yes'], [20, 'No'], [100, 'Maybe']]
print("Sorted List B based on index 1: % s" % (sorted(B, key=itemgetter(1))))

How to sort a list in python

l=[1,3,2,5]
l= sorted(l)
print(l)
#output=[1, 2, 3, 5]
#or reverse the order:
l=[1,3,2,5]
l= sorted(l,reverse=True)
print(l)
#output=[5, 3, 2, 1]

How to sort a list of lists in python

# You can use a lambda function, but you'll have to specify the index of the sorting key.

A = [[100, 'Yes'], [40, 'Maybe'], [60, 'No']]
print("Sorted List A based on index 0: % s" % (sorted(A, key=lambda x:x[0])))
B = [[2, 'Dog'], [0, 'Bird'], [7, 'Cat']]
print("Sorted List A based on index 1: % s" % (sorted(B, key=lambda x:x[1])))

# Also, you can use .sort() if you want to sort just by the first index

A = [[55, 90], [45, 89], [90, 70]]
A.sort()
print("New sorted list A is % s" % (A))
A.sort(reverse=True)
print("New reverse sorted list A is % s" % (A))

# You can even change the key sort, if you want to sort by length for example:

A = [[5, 90, 'Hi', 66], [80, 99], [56, 32, 80]]
A.sort(key=len) # <-
print("New sorted list A is % s" % (A))

Source: delftstack.com

Python Sort Lists

thislist = ["orange", "mango", "kiwi", "pineapple", "banana"]
thislist.sort()
print(thislist)

-1

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