Pronic number program in python

n = int(input("Enter a number: "))
f = 0
for i in range(n):
    if i * (i + 1) == n:
        f = 1
        break

if f==1:
    print("Pronic number")
else:
    print("Not a Pronic number")

Source: codespeedy.com

Similar codes

0 vote191 views2 answers
Flask api abort
Python
0 vote199 views1 answer
Spyder - identation
Python
3 votes184 views2 answers
Moving element to last position in a list python
Python
15 votes202 views3 answers
Numpy to csv
Python
1 vote195 views1 answer
Python 3d array
Python
4 votes194 views2 answers
Finding median on python
Python
0 vote214 views1 answer
How to use python-socker.io with fast api
Python
34 votes204 views6 answers
Flask example
Python
0 vote197 views1 answer
Pandas difference between subsequent lines
Python
0 vote212 views2 answers
I type nano in python and o get error
Python