Pronic number program in python

n = int(input("Enter a number: "))
f = 0
for i in range(n):
    if i * (i + 1) == n:
        f = 1
        break

if f==1:
    print("Pronic number")
else:
    print("Not a Pronic number")

Source: codespeedy.com

Similar codes

0 vote138 views2 answers
Save image from jupyter notebook
Python
1 vote120 views1 answer
Python how to draw triangle
Python
0 vote128 views1 answer
Dynamic grid using tkinter
Python
6 votes130 views3 answers
Flask get ip of user
Python
0 vote146 views1 answer
Make tkinter text editing disabled
Python
0 vote120 views1 answer
How to sum only the odd values in python
Python
0 vote125 views1 answer
A string varible in python
Python
2 votes126 views1 answer
Pandas remove timezone info
Python
0 vote134 views1 answer
How to create a scoreboard for the top 5 players in python
Python
3 votes152 views2 answers
Ros python subscriber
Python