/TypeScript/Check if breckets clossing properly

Check if breckets clossing properly

def valid_paren(input_str):
  # Declaraing a stack.
  stack = []
  # Iterating over the entire string
  for paren in input_str:
    # If the input string contains an opening parenthesis,
    # push in on to the stack.
    if paren == '(' or paren == '[' or paren == '{':
      stack.append(paren)
    else:
      # In the case of valid parentheses, the stack cannot be 
      # be empty if a closing parenthesis is encountered.
      if not stack:
        print(input_str, "contains invalid parentheses.")
        return
      else:
        # If the input string contains a closing bracket,
        # then pop the corresponding opening parenthesis if
        # present.
        top = stack[-1]
        if paren == ')' and top == '(' or \
        paren == ']' and top == '[' or \
        paren == '}' and top == '{':
          stack.pop()
  # Checking the status of the stack to determine the
  # validity of the string.
  if not stack:
    print(input_str, "contains valid parentheses.")
  else:
    print(input_str, "contains invalid parentheses.")

input1 = "{{}}()[()]"
input2 = "{][}"
input3 = ")"
valid_paren(input1)
valid_paren(input2)
valid_paren(input3)

Check if breckets clossing properly

def valid_paren(input_str):
  # Declaraing a stack.
  stack = []
  # Iterating over the entire string
  for paren in input_str:
    # If the input string contains an opening parenthesis,
    # push in on to the stack.
    if paren == '(' or paren == '[' or paren == '{':
      stack.append(paren)
    else:
      # In the case of valid parentheses, the stack cannot be 
      # be empty if a closing parenthesis is encountered.
      if not stack:
        print(input_str, "contains invalid parentheses.")
        return
      else:
        # If the input string contains a closing bracket,
        # then pop the corresponding opening parenthesis if
        # present.
        top = stack[-1]
        if paren == ')' and top == '(' or \
        paren == ']' and top == '[' or \
        paren == '}' and top == '{':
          stack.pop()
  # Checking the status of the stack to determine the
  # validity of the string.
  if not stack:
    print(input_str, "contains valid parentheses.")
  else:
    print(input_str, "contains invalid parentheses.")

input1 = "{{}}()[()]"
input2 = "{][}"
input3 = ")"
valid_paren(input1)
valid_paren(input2)
valid_paren(input3)

input4 = "([)]"valid_paren(input4)input5 = '() [{}]'valid_paren(input5)

Similar codes

0 vote324 views2 answers
Integrationtest typescript
TypeScript
0 vote194 views1 answer
In grunt cannot be loaded because running scripts is disabled on this system
TypeScript
0 vote226 views1 answer
Add column if not exists postgresql
TypeScript
1 vote203 views1 answer
Nuxt "AxiosRequestConfig"
TypeScript
3 votes213 views1 answer
Rospy create package
TypeScript
8 votes216 views3 answers
Initialize all elements of vector to 0 c++
TypeScript
0 vote206 views1 answer
Javax.validation.constraints does not exist
TypeScript
9 votes209 views4 answers
Error TS2564: Property 'description' has no initializer and is not definitely assigned in the constructor. in angular class
TypeScript
0 vote263 views1 answer
A korean movie where a man gets kidnapped by a family
TypeScript
0 vote198 views1 answer
Engineering adding requirements to password
TypeScript