/Python/Python code for create diamond shape with integer

Python code for create diamond shape with integer

n = 9
print("Pattern 1")
for a1 in range(1, (n+1)//2 + 1): #from row 1 to 5
    for a2 in range((n+1)//2 - a1):
        print(" ", end = "")
    for a3 in range((a1*2)-1):
        print("*", end = "")
    print()

for a1 in range((n+1)//2 + 1, n + 1): #from row 6 to 9
    for a2 in range(a1 - (n+1)//2):
        print(" ", end = "")
    for a3 in range((n+1 - a1)*2 - 1):
        print("*", end = "")
    print()

Source: stackoverflow.com

Diamond shape in python

def p(n):
    for i in range(n):
        print(" "*(n-i-1),end="")
        print("* "*(i+1))
        
    for j in range(n-1, 0, -1):
        print(" "*(n-j),end="")
        print("* "*(j))

star_num = int(input("Enter a number that shows diameters of your diamond shape: "))
print(p(star_num))

Similar codes

1 vote214 views2 answers
Tensor get value
Python
1 vote216 views1 answer
Django sessions for beginners
Python Django
0 vote158 views1 answer
Django serve media folder
Python
7 votes180 views3 answers
Lambda and function in python
Python
0 vote170 views3 answers
H2o ai python
Python
2 votes167 views2 answers
Pyqt5 qtwebenginewidgets not found
Python
0 vote117 views1 answer
Django admin manytomanyfield filter
Python
0 vote281 views1 answer
How to access pandas column
Python
1 vote163 views3 answers
Typeerror:
Python
3 votes173 views1 answer
Tkinter labelframe
Python