Following Links in Python

import urllib
from BeautifulSoup import *

URL = raw_input("Enter the URL:") #Enter main URL
link_line = int(raw_input("Enter position:")) - 1 #The position of link relative to first link
count = int(raw_input("Enter count:")) #The number of times to be repeated

while count >= 0:
    html = urllib.urlopen(URL).read()
    soup = BeautifulSoup(html)
    tags = soup('a')
    print URL
    URL = tags[link_line].get("href", None)
    count = count - 1

Source: gist.githubusercontent.com

Similar codes

0 vote203 views1 answer
Monthly precipitation in python
Python
1 vote188 views1 answer
Python how to check if a functions been called
Python
4 votes221 views2 answers
Python code to open windows command prompt
Python
0 vote188 views1 answer
Networkx - remove small components from a graph
Python
0 vote207 views1 answer
IndexError: tuple index out of range
Python
0 vote261 views1 answer
Django table view sort filter
Python Django
1 vote252 views1 answer
Dot notation python
Python
0 vote221 views2 answers
Spacy french stopwords
Python
0 vote204 views3 answers
How to remove trailing zeros in python
Python
0 vote181 views1 answer
How to get session value in django template
Python