Following Links in Python

import urllib
from BeautifulSoup import *

URL = raw_input("Enter the URL:") #Enter main URL
link_line = int(raw_input("Enter position:")) - 1 #The position of link relative to first link
count = int(raw_input("Enter count:")) #The number of times to be repeated

while count >= 0:
    html = urllib.urlopen(URL).read()
    soup = BeautifulSoup(html)
    tags = soup('a')
    print URL
    URL = tags[link_line].get("href", None)
    count = count - 1

Source: gist.githubusercontent.com

Similar codes

0 vote194 views1 answer
Try: if '1' != 1: raise "someError" else: print("someError has not occurred") except "someError": print ("someError has occurred")
Python
3 votes164 views3 answers
Convert list to string separated by comma python
Python
0 vote202 views1 answer
Multiprocessing print does not work
Python
1 vote192 views1 answer
Slicing in python listing
Python
0 vote224 views1 answer
Install python 3.6 ubuntu 16.04
Python
1 vote183 views1 answer
A0 = dict(zip(('a','b','c','d','e'),(1,2,3,4,5)))
Python
19 votes198 views6 answers
.pop python
Python
0 vote178 views1 answer
Python code pycharm
Python
19 votes267 views6 answers
Pip install django
Python Django
11 votes188 views4 answers
Macos set default python version
Python