Python loc id in list

In [30]: df = pd.DataFrame({'subscriber_id':[1,2,3,4,5]})
'''   	subscriber_id
	0              1
	1              2
	2              3
	3              4
	4              5 '''

mask = df['subscriber_id'].isin([2,4,5])
''' 0    False
	1     True
	2    False
	3     True
	4     True '''

df.loc[mask]
'''	   subscriber_id
	1              2
	3              4
	4              5 '''

Source: stackoverflow.com

Similar codes

0 vote165 views1 answer
Compute difference of all the combinations of 2 arrays
Python
6 votes165 views2 answers
Horizontal line matplotlib python
Python
1 vote164 views1 answer
Stack overflow python timedate
Python
0 vote211 views1 answer
Python conditions symbols
Python
257 votes453 views23 answers
Drop column pandas
Python
1 vote170 views1 answer
Codeforces - 570b python
Python
-1 vote174 views1 answer
How to add one 2d list to another 2d list python
Python
0 vote248 views2 answers
Django admin image
Python Django
0 vote179 views1 answer
Pylatex add package
Python
15 votes153 views4 answers
Django python install
Python