Python loc id in list

In [30]: df = pd.DataFrame({'subscriber_id':[1,2,3,4,5]})
'''   	subscriber_id
	0              1
	1              2
	2              3
	3              4
	4              5 '''

mask = df['subscriber_id'].isin([2,4,5])
''' 0    False
	1     True
	2    False
	3     True
	4     True '''

df.loc[mask]
'''	   subscriber_id
	1              2
	3              4
	4              5 '''

Source: stackoverflow.com

Similar codes

-1 vote178 views1 answer
Phyton datetime comparison
Python
5 votes172 views3 answers
Python transpose list
Python
0 vote198 views1 answer
Mail.send_message flask not working, SSL ==> 465
Python Flask
0 vote169 views1 answer
Matplotlib radial averaging
Python
1 vote195 views2 answers
Zip django template
Python Django
1 vote175 views2 answers
{:.1%} print one decimal pandas
Python
0 vote174 views1 answer
TypeError: unhashable type: 'list' drop duplicates
Python
0 vote169 views1 answer
Py - count if a word is present in a column
Python
-1 vote204 views2 answers
Django view
Python Django
0 vote198 views1 answer
The webpage at http://127.0.0.1:8000/ might be temporarily down or it may have moved permanently to a new web address. django
Python Django