Python loc id in list

In [30]: df = pd.DataFrame({'subscriber_id':[1,2,3,4,5]})
'''   	subscriber_id
	0              1
	1              2
	2              3
	3              4
	4              5 '''

mask = df['subscriber_id'].isin([2,4,5])
''' 0    False
	1     True
	2    False
	3     True
	4     True '''

df.loc[mask]
'''	   subscriber_id
	1              2
	3              4
	4              5 '''

Source: stackoverflow.com

Similar codes

0 vote153 views1 answer
Pass arguments with apply
Python
0 vote142 views1 answer
Z transform in python
Python
0 vote174 views1 answer
Django serializer get image list
Python Django
0 vote134 views1 answer
How remove spaces python input
Python
-1 vote151 views1 answer
Binascii.Error: Incorrect padding in python django
Python
0 vote152 views1 answer
Loading model
Python
1 vote145 views1 answer
How to create obtain any random 3 items of list in python
Python
0 vote104 views1 answer
Jinja for items in list
Python
0 vote147 views1 answer
Updating file multiple times in pandas
Python
1 vote183 views1 answer
Python saveAsTextFile
Python