Python loc id in list

In [30]: df = pd.DataFrame({'subscriber_id':[1,2,3,4,5]})
'''   	subscriber_id
	0              1
	1              2
	2              3
	3              4
	4              5 '''

mask = df['subscriber_id'].isin([2,4,5])
''' 0    False
	1     True
	2    False
	3     True
	4     True '''

df.loc[mask]
'''	   subscriber_id
	1              2
	3              4
	4              5 '''

Source: stackoverflow.com

Similar codes

0 vote93 views1 answer
Python extract mails from string
Python
0 vote126 views1 answer
Dataframe rolling first eleemnt
Python
0 vote183 views1 answer
Converting column data to sha256 pandas
Python
0 vote172 views2 answers
Count values python
Python
-1 vote123 views1 answer
Sorting numbers in python without sort function
Python
2 votes115 views1 answer
Fromkeys in python
Python
5 votes125 views1 answer
Show full pd dataframe
Python
0 vote136 views3 answers
Repeat
Python
0 vote126 views1 answer
Resize multiple images to same size python
Python
0 vote120 views1 answer
Return the indices of the bins
Python